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This section is for Grade 3-4 (approx. age 10 to 12)
The correct answer is (C).
The image below shows the compartments where Victoria puts the bracelets from options
(A), (B) and (D). Observe that the bracelets and the compartments have the same color pattern.
Note there is no compartment with the color pattern black-white in Victoria’s box, so there is no compartment for the bracelet in option (C) to match.
The correct answer is C.
First, we need to figure out how to get the correct sequence. We do this by:
1. Find the letter on the keyboard.
2. If the letter is NOT at beginning of the row, then type the letter to the LEFT. If the letter is at the beginning of the row, then type the letter at the end of the row.
3. Repeat these steps for each letter in the word.
This gives the correct answer as:
In option A, the second sequence is not correct: R & T are being used as if there was no keyboard malfunction.
In option B the first sequence is not correct: MW gives us OE instead of the EO in PIGEON
In option D the three sequences are not correct. They apply the opposite rule of the malfunction.
B) is correct because each side of each part matches.
A) is incorrect because there are no stripes on the bottom part
C) is incorrect because on the left hand side of the dark part there is not a part, which is
lightly colored.
D) is incorrect. According to the image in the task the blue and the light must be connected, which they are not in this image.
The correct answer is C)
Only animals of the same type arrive together.
Only the springbok uses the salt block. Only the ostrich eats the corn. The giraffe is the only one that does not eat the lucerne but eats the tree leaves. Only the springbok can eat the lucerne and the bush leaves. Only the warthog digs for roots.
Answer A is wrong because the giraffe does not eat lucerne or corn.
Answer B is wrong because the third animal, the warthog does not eat the bush leaves (it is
too short) and subsequently, the springbok cannot dig for roots.
Answer D is wrong because already the first animal, the giraffe, does not go for the lucerne or the salt block (it could not bend so much down to the ground)
This section is for Grade 5-6 (approx. age 12 to 14)
The correct answer is B)
Only on the card B the values of each attribute are noted in the right kind.
• Answer A), C) and D): The Ricca named Lori has 2 horns , the information is correct, but not noted in the correct kind.
• Answer A): The Ricca named Lori has eyes , the information ✓ is correct, but the correct kind is number, so the value has to be a number. 3 is the correct value.
Correct answer is D) S, E, E, S
All paths of different colors and different styles are shown in the picture.
The correct path (D) to the treasure is shown on the picture by green path. All other paths (yellow (A), blue (B), and red dashed (C)) lead the pirate into the sea. The pirate would be on one of the X mark in the sea at end of the first, second, or third instruction step.
We don’t need to know how long a mile is on the picture. It can be understood from the task statement that the four steps are all of equal distance. Since all answers contain two E’s and two S’s, an invisible 2x2 grid can be drawn with the pirate and the treasure box as two diagonally opposite corners. It is easy to see that only by going through the center point, can the pirate avoid falling into the sea.
Correct answer is 18 (actions).
This is the sentence that correctly states what the picture shows:
“Tom has two apples and four limes but Mary has three apples and three bananas.”
To use the smallest number of actions, we need to remove words from the incorrect sentence in such a way that the highest possible number of words remain.
Working from left to right along the sentence, we find that there are 6 words that already occur in the order we need them in to construct the correct sentence:
“Tom has three apples and two limes but Mary has four apples and four bananas”
These can be left at the beginning of the sentence by deleting the other words that are not highlighted.
“Tom has three apples and two limes but Mary has four apples and four bananas.”
The correct sentence does have the same number of words as the wrong one, however. Hence, the deleted nine words need to be replaced by new words in the correct order from the word bank. So we need to delete nine words and then add nine words to replace the previously deleted words. We need to perform a total of 9 + 9 = 18 actions.
Answer: E. Hannah
Based on the what can be seen on the computer screen, we know who each student sits next to.
From the view below, we know that James is sitting next to Emma.
From the view below, we know that Emma is sitting between James and Diana.
Using the same method with the rest of the views, we can see all 9 students in this order:
The one who sits in the middle is the one at the 5th position from left, or the 5th position from right.
That person is Hannah.
This section is for Grade 7-8 (approx. age 14 to 16)
5 days (correct answer, height of the binary tree): At the end of each day, a stem with two
new buds has grown out of each bud of the miracle flower. You only have to follow one
branch, e.g. the rightmost one, to count the days of growth.
11 days (wrong answer, total number of buds and stems for one branch)
16 days (wrong answer, number of outer stems)
32 days (wrong answer, number of outer buds)
The background shown in answer C is not completely built according to the diagram.
A tile with a diamond on it can only be followed by , which is not the case here.
There are several ways to find the solution of this task. A straightforward strategy is to try each given background image and check each tile against the diagram to see if it is valid. The quickest way is this: You check the tiles in the diagram starting with the tiles from which only one arrow emanates. Think of theses arrows as constraints. A → B means “Tile A must be followed by Tile B”. Then check if this constraint holds for each background image.
Oliver’s rattle is in picture A).
When balls go through the rattle, they cannot change their order. So you only need to check the order of all balls. After the red ball comes the yellow one , after the yellow one is the green one . After the green one is the blue one and after the blue one is the purple one . After the purple ball there is the red one again. Let’s look at the order of the balls starting from the red one. When we reach the end, we will go back to the start.
In answer A), the balls are in the correct order.
In answer B), there is the blue ball after the yellow one, but there should be the green ball.
In answer C), the red and the yellow ball are not together.
In answer D), even though the red and the yellow ball are together, they are in a different direction.
This could be OK, if we flip the rattle, as it is a see-through from both sides. But before the yellow ball, there is the purple ball instead of the green one.
Answer D is correct: 6 beads.
We can make up all Bebracelets that can be made in this case and see which ones have the largest number of beads.
The first bead from the tube has number 5. If it is put on the string, only beads 6, 7, 8, and 9 can be put on the string afterwards, with two possible bead sequences that can be on the string in the end: 5679, and 589. If bead 5 is put aside, and the next bead (1) is put on the string first, there are more and longer possible sequences, as shown here:
If any other bead is put on the string first, the longest possible final sequence is already included in one of those above, starting with either #1 or #5. For example, putting bead #2 on the string first leads to sequences such as 24679 or 2489, both of which are included in one of the longer sequences above (124679 and 12489, respectively).
From this, we figure out that the Bebracelets with the largest number of beads from the given tube start with bead 1 and consist of 6 beads each: 124679, and 123679.
This section is for Grade 9-11 (approx. age 16 to 18)
The answer is 4
Captain Boris should enter letters of half of the regions to the device first. There could be two scenarios.
a. If the device indicates that the treasure is in the given regions, the captain now further divides this region into two
halves and enters one half to the device.
b. If the device indicates that the treasure in not in the given regions, he splits the remaining regions into two halves and enters one of the halves to the device.
The Captain continues the above till he finds the region that has the treasure.
For example, if he enters A,B,C,D,E,F,G,H to the device and it returns a "no", he could enter K,L,O,P to the device (any remaining 4 regions would do). If it returns "no" again, he further divides the remaining regions and enter any 2 of the remaining regions to the device (for example J,N as shown). If the device returns "no", the treasure is hidden in one of the remaining regions I or M. If he enters M and the device returns no, he now knows for sure that the treasure is in region I.
The correct answer is D.
The 1st ball will go down the most left-hand path. This will change the gate 1 and gate 2 to
the right.
As gate 1 has been changed, the 2nd ball will go to the right, but then left at the gate 3. This
will change gate 1 back to left and gate 3 to right.
The 3rd ball will be sent left at gate 1 and right at gate 2. This will change gate 1 to right and gate 2 to left.
The 4th ball will be sent to the right at gate 1 and will continue right at gate 3. This will change gate 1 and gate 3 to left.
The 5th ball will be sent down the left-hand path.
Answer A is incorrect because it will create this incorrect pattern:
Answer B is incorrect because it will create this incorrect pattern:
Answer C is incorrect because it will create this incorrect pattern:
The correct answer is BEAVERDAM.
From the task we know that if the alarm is sounded after n seconds, then the Burglar Beaver is guaranteed that the first n – 1 letters of his guess are correct and the nth letter is wrong. We illustrate this with an example:
- When the alarm sounds after 3 seconds, here's what happened:
- After 1 second, the first letter of the guessed code has been compared with the first letter of the secret code. The
- alarm not sounding means that the first letter of his guess is correct.
- After 2 seconds, the second letter has been compared. The alarm not sounding means that the second letter of his
- guess is also correct.
- After 3 seconds, the third letter has been compared . The alarm sounding means that the third letter of his guess is
- wrong.
Using this reasoning, we can construct a table to systematically identify the first letters of the secret code. The underlined letters in the "Guess" column refer to those that are guaranteed to be correct.
Guess | Number of Seconds Before Alarm | First 9 Letters of Secret Code |
*CORN*DOG*** | 1 | ********* |
******DOG*** | 8 | ******D** |
*E*VER*Y**** | 7 | *E*VERD** |
*E*VER*Y**** | 7 | *E*VERD** |
***VER*Y**** | 2 | *E*VERD** |
BE*B*R*AS*** | 4 | BE*VERD** |
*****R*AS*** | 9 | BE*VERDA* |
**A***DAM*** | 5 | BEAVERDA* |
********M*** | 10 | BEAVERDAM |
Correct answer: 16
16 beavers went to the Forest.
To figure out how many beavers have taken each path, we marked the intersections with letters A, B, …, F. Because a beaver can move on each path only in one direction, shown by the arrow, each beaver can visit each intersection only once.
The beavers that went to the forest must have gone through F or E. To get to F, one must arrive through C or D. We know that 4 beavers arrived from C (and thus do not even need to backtrack further from C). However, we do not know how many arrived from D.
Let's look at the paths connected to intersection D. From a beaver’s house, there are 9 beavers that went to intersection D. So there are 9 beavers that have to leave intersection D. We can see that there are 3 paths leaving intersection D: D to C (2 beavers), D to E (6 beavers) and D to F, where the number is missing. Since there are 9 beavers leaving intersection D and there are already 2 + 6 beavers leaving, there is only one beaver that takes the D to F path (9 – (2 + 6) = 1).
Now let's look at path from F to Forest. We can see that there are 4 + 1 beavers that went to F: 4 beavers from C and 1 beaver from D. From F, 3 beavers went to the museum, which means that 2 beavers went to the forest (5 – 3 = 2).
We still need to find out how many beavers went to the Forest from intersection E. There are 6 beavers that went from D to E and because 8 beavers went to B from the house, 8 beavers went from B to E as it is the only way. In total, 6 + 8 = 14 beavers went to E, which means that 14 beavers went from E to the Forest as this is the only path available.
Summing up the numbers of beavers that went from F to Forest and from E to Forest, there are 2 + 14 = 16 beavers went to Forest. The final answer is 16.